(-2/5)+(3x/20)+(-3/10)=(x/5)+(x^2/4)

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Solution for (-2/5)+(3x/20)+(-3/10)=(x/5)+(x^2/4) equation: 


x in (-oo:+oo)

(3*x)/20-2/5-3/10 = (x^2)/4+x/5 // - (x^2)/4+x/5

(3*x)/20-((x^2)/4)-(x/5)-2/5-3/10 = 0

-1/4*x^2-1/20*x-7/10 = 0

DELTA = (-1/20)^2-(-7/10*(-1/4)*4)

DELTA = -279/400

DELTA < 0

x belongs to the empty set

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